Python Script Another Discrepency

[silenuznowan]

(04-01-2025, 09:36 PM)Ofnuts Wrote: It looks like you are using the PDB to make API calls. This is unnecessary, and terribly protracted. This also means that the returned value is a tuple with 1) a status (PDBStatusType.SUCCESS) and 2) the value you want: (<Gimp.GroupLayer object at 0x7f70a7ebb180 (GimpGroupLayer at 0x5561a26ba060)>) .

So either:

• you unpack all you calls: success, group = procedure.run(config);
  
• you forego the PDB (just usable to call plugins) and use the API directly: group=layer.get_parent()
  

Choose wisely. The "direct" API is described here: Gimp – 3.0

I'm following the docs my function looks like this:

Code:

def insert_layer(image: Gimp.Image, layer: Gimp.Layer, parent: Gimp.Layer, position: int = 0) -> bool:    
    procedure = Gimp.get_pdb().lookup_procedure('gimp-image-insert-layer')
    config = procedure.create_config()
    config.set_property('image', image)
    config.set_property('layer', layer)
    config.set_property('parent', parent)
    config.set_property('position', position)
    result = procedure.run(config)
    success = result.index(0)
    return success

And Is_group

Code:

def is_group_item (item: Gimp.Item):
    procedure = Gimp.get_pdb().lookup_procedure('gimp-item-is-group');
    config = procedure.create_config();
    config.set_property('item', item);
    result = procedure.run(config);
    success = result.index(0);
    group = result.index(1)
    return group

So I'm not sure what your suggesting I do differently.

Also how do I now get a name of the layer?  layer.name results in an error that attribute is not found.

Thanks for the pointer to the direct api docs that looks good. Solved my getting the name problem.
Thanks.